Merry Christmas + Solutions

I hope you'll enjoy your Rubik's holidays!! :D

We'll meet again in 5/2 weeks. Meanwhile, don't let yourselves be hunted by badgers XD

Christmas Homework - Day 1 Solutions
I'm sorry for this delay. The  incident wasn't due to myself forgetting about uploading the solutions, but to
a very important fact: I'm in Ponferrada and it was absolutely impossible to get an internet connection until today ;P

If you want to check your day 1 exercises, click here.


Christmas Homework - Day 2 Solutions
We've reached Christmas' equator!! Day 2 solutions are followed by a classic anthem from my high school times XD
If you want to check your day 2 exercises, click here.

 Ecuador by Sash!!

Christmas Homework - Day 3 Solutions

Time is running out guys!!

If you want to check your day 3 exercises, click here.

PS: if your own solutions don't match with that ones in the pdf, and you're completely sure you've done the exercises in their right way, post a comment to this entry ;) Also if you have any doubt, you should share it with us :D

Be seeing you!!!!

Polynomials Exam Results

Hi guys! I'm attaching here your last exam marks. You succeeded on scoring a high arithmetic mean, but some of you did actually low your usual results.... Maybe you felt too confindent and you didn't study enough at home... on Monday you'd better tell me!

Anyway, congratulations to those who managed to improve your mark ;D

AB01	6,8
AB02	7,4
AB03	6,5
AB04	5,4
AB05	8,2
AB06	7,6
AB07	7,1
AB08	10,5
AB09	4,1
AB10	8
AB11	8,2
AB12	7,8
AB13	3
AB14	10,3
AB15	4,2
AB16	7,6
AB17	8,6
AB18	6,9
AB19	6,1
AB20	10,2
AB21	6,8
AB22	5,1
AB23	6,1
AB24	9
AB25	8,3

Good afternoon-night, class(;
Sorry because I didn't do the post before, but I couldn't do it.

Today we have started a new unit. Unit 4; the equiations.
We saw that an equality is composed of two algebraic expressions united by the equal sign and they can be True, or False; and Identities, or Equations.
Then, we saw the parts of an equation:

2x-3=3x+2

The first part; "2x-3" is the first member and it's composed by two terms, "2x" and "-3".

The second part; "3x+2" is the second member and of course it's composed by two other terms; "3x" and "+2".

If the equations have the same solution, they are called "equivalent equation".

Then, we copied some of the rules of the equivalent equations, but we didn't have time to finish that part.

Luckly, Mario didn't send us homework(;

Global Exam Results

Hi class! I've just finished your Global Exams correction ;) You'll have the chance to check your operations and (sometimes) imagination next Monday. Meanwhile, I'm posting here the results:

AB01	6,2
AB02	8,4
AB03	7,4
AB04	7,9
AB05	9,4
AB06	6,3
AB07	8,4
AB08	10
AB09	8,6
AB10	7,5
AB11	3,8
AB12	9,2
AB13	5,3
AB14	9,3
AB15	5,3
AB16	6,9
AB17	7,8
AB18	6,9
AB19	6,6
AB20	9,9
AB21	5,8
AB22	6,8
AB23	7,8
AB24	9,1
AB25	7,3

I've had no time at all to review your notebooks, so feel yourselves free to enjoy a weekend without maths homework :P

T.G.I.F!!

Attending to Monica's request, I've just add an incredible Finnish song: Sonata Arctica's Full Moon. I love this video! If you try to follow the misheard lyrics it really seems they sing what it's written XD

Prime Number Shitting Bear + New Challenge

Have you ever wondered about how many prime numbers may exist?

Well, I guess you haven't, but if you'd like to find out, you should visit a maths classic: The Prime Number Shitting Bear

NEW CHALLENGE

Let's finish this "numbers" units with this short challenge:

Can you find out the final result of the following opeartion?

$$\left(1-\frac{1}{2} \right) \cdot \left(1-\frac{1}{3} \right) \cdot \left(1-\frac{1}{4} \right) \cdots \left(1-\frac{1}{999} \right) \cdot \left(1-\frac{1}{1000} \right)$$ 

It's easier than it looks!

As always, you must send me your answer to my e-mail and post a comment to this entry ;)
DEADLINE: 1st of December.

Allo and Maite were the only ones who answered the previous challenge. Congratulations guys! You've earned another positive ;)

Hi class:)

I´m going to talk about today class.

First we have corrected our yesterday homework that was exercise number 55.Then Mario has explained us how to remove the common factor: we can remove the common factor to a polynomial expression in order to get an easier one.

This is an example: $$4x^{2}y+2xy-4xy^{4}=2xy(2x+1-2y^{3})$$

it means the you have to found one common factor on the polynomial and then you have to divide the polynomial between the common factor.

And after that Mario has explained to us the remarkable identities.

Example: $$(a+b)^{2}=(a+b)(a+b)=a^{2}+ab+ba+b^{2}=a^{2}+b^{2}+2ab$$

the explanation of the result of the operation is that you have to multiply all the factors by each other , it means that: $(a \cdot a) + (a \cdot b) + (b \cdot a) + (b \cdot b) = a^{2} + b^{2}+2ab$

I hope you have understood it.

Let's run a poll to find out who really wants this blog-project to continue

I would really like to give this blog and other "different" activities a sencond chance... would you?

If this works, I guess we can try to finish """"that"""" blog activity to learn how to write expressions like:


$$\Huge{P(x)=-\frac{2}{4}x^{4}+5x^{2}-3x+1},$$

so our blog looks more... professional.

It's up to you!!

Meanwhile (I mean, while you think your answer to this poll) you may listen to this Loituma's Classic Finnish song (one of the most difficult languages in the whole universe)

Maybe the song rings the bell with you... that's because there's a Disco version called Holly Dolly Song!

Be seeing you!!